InfyTQ 2020

Coding questions   Question 1 (Even-Odd series):  Given a string and it contains the digits as well as non-digits. We have to find the count of non-digits. If it is odd then remove all the non-digits and print the string as in even-odd order.If it is even then print the string as in odd-even order. E.g.  The given string is  */24#5%7&9*3@ . We have to count the non-digit. It’s 7, odd. Then remove all the digits from the string and output will become (in a string) 254739. In the problem, we have only 2 even and 4 odd numbers then after the even number of completion print the remaining odd numbers. Solution:  This is a basic question and the time complexity is O(n) Python string = input ()  characters = [] even = [] odd = [] for i in string:      if i.isdigit():          if int (i) % 2 = = 0 :              even.append(i)  ...